(x^2-2x)^2-8=7(x^2-2x)

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Solution for (x^2-2x)^2-8=7(x^2-2x) equation: 



(x^2-2x)^2-8=7(x^2-2x)

We move all terms to the left:

(x^2-2x)^2-8-(7(x^2-2x))=0



We calculate terms in parentheses: -(7(x^2-2x)), so:

7(x^2-2x)

We multiply parentheses

7x^2-14x

Back to the equation:

-(7x^2-14x)



We get rid of parentheses

-7x^2+(x^2-2x)^2+14x-8=0

We add all the numbers together, and all the variables

-7x^2+14x+(x^2-2x)^2-8=0

We move all terms containing x to the left, all other terms to the right

-7x^2+14x+(x^2-2x)^2=8

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